【小学3年】同じ分母の分数のたし算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle \frac{1}{10} + \frac{7}{10} \) =
- (2) \(\displaystyle \frac{9}{11} + \frac{1}{11} \) =
- (3) \(\displaystyle \frac{1}{5} + \frac{2}{5} \) =
- (4) \(\displaystyle \frac{1}{3} + \frac{1}{3} \) =
- (5) \(\displaystyle \frac{5}{9} + \frac{1}{9} \) =
- (6) \(\displaystyle \frac{3}{6} + \frac{1}{6} \) =
- (7) \(\displaystyle \frac{2}{4} + \frac{1}{4} \) =
- (8) \(\displaystyle \frac{8}{10} + \frac{1}{10} \) =
- (9) \(\displaystyle \frac{2}{10} + \frac{3}{10} \) =
- (10) \(\displaystyle \frac{2}{12} + \frac{3}{12} \) =
【解答】【小学3年】同じ分母の分数のたし算プリント
日付:
次の計算をしなさい。
- (1) \( \displaystyle \frac{1}{10} + \frac{7}{10} \) = \(\displaystyle \frac{8}{10} \)
- (2) \( \displaystyle \frac{9}{11} + \frac{1}{11} \) = \(\displaystyle \frac{10}{11} \)
- (3) \( \displaystyle \frac{1}{5} + \frac{2}{5} \) = \(\displaystyle \frac{3}{5} \)
- (4) \( \displaystyle \frac{1}{3} + \frac{1}{3} \) = \(\displaystyle \frac{2}{3} \)
- (5) \( \displaystyle \frac{5}{9} + \frac{1}{9} \) = \(\displaystyle \frac{6}{9} \)
- (6) \( \displaystyle \frac{3}{6} + \frac{1}{6} \) = \(\displaystyle \frac{4}{6} \)
- (7) \( \displaystyle \frac{2}{4} + \frac{1}{4} \) = \(\displaystyle \frac{3}{4} \)
- (8) \( \displaystyle \frac{8}{10} + \frac{1}{10} \) = \(\displaystyle \frac{9}{10} \)
- (9) \( \displaystyle \frac{2}{10} + \frac{3}{10} \) = \(\displaystyle \frac{5}{10} \)
- (10) \( \displaystyle \frac{2}{12} + \frac{3}{12} \) = \(\displaystyle \frac{5}{12} \)