【小学3年】同じ分母の分数のたし算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle \frac{8}{10} + \frac{1}{10} \) =
- (2) \(\displaystyle \frac{1}{6} + \frac{1}{6} \) =
- (3) \(\displaystyle \frac{3}{5} + \frac{1}{5} \) =
- (4) \(\displaystyle \frac{3}{12} + \frac{6}{12} \) =
- (5) \(\displaystyle \frac{2}{6} + \frac{3}{6} \) =
- (6) \(\displaystyle \frac{2}{11} + \frac{1}{11} \) =
- (7) \(\displaystyle \frac{6}{10} + \frac{2}{10} \) =
- (8) \(\displaystyle \frac{5}{9} + \frac{3}{9} \) =
- (9) \(\displaystyle \frac{6}{10} + \frac{1}{10} \) =
- (10) \(\displaystyle \frac{5}{7} + \frac{1}{7} \) =
【解答】【小学3年】同じ分母の分数のたし算プリント
日付:
次の計算をしなさい。
- (1) \( \displaystyle \frac{8}{10} + \frac{1}{10} \) = \(\displaystyle \frac{9}{10} \)
- (2) \( \displaystyle \frac{1}{6} + \frac{1}{6} \) = \(\displaystyle \frac{2}{6} \)
- (3) \( \displaystyle \frac{3}{5} + \frac{1}{5} \) = \(\displaystyle \frac{4}{5} \)
- (4) \( \displaystyle \frac{3}{12} + \frac{6}{12} \) = \(\displaystyle \frac{9}{12} \)
- (5) \( \displaystyle \frac{2}{6} + \frac{3}{6} \) = \(\displaystyle \frac{5}{6} \)
- (6) \( \displaystyle \frac{2}{11} + \frac{1}{11} \) = \(\displaystyle \frac{3}{11} \)
- (7) \( \displaystyle \frac{6}{10} + \frac{2}{10} \) = \(\displaystyle \frac{8}{10} \)
- (8) \( \displaystyle \frac{5}{9} + \frac{3}{9} \) = \(\displaystyle \frac{8}{9} \)
- (9) \( \displaystyle \frac{6}{10} + \frac{1}{10} \) = \(\displaystyle \frac{7}{10} \)
- (10) \( \displaystyle \frac{5}{7} + \frac{1}{7} \) = \(\displaystyle \frac{6}{7} \)