【小学5年】異なる分母の分数のひき算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle 1 \frac{4}{7} - 1 \) =
- (2) \(\displaystyle \frac{2}{7} - \frac{1}{8} \) =
- (3) \(\displaystyle \frac{2}{8} - \frac{1}{8} \) =
- (4) \(\displaystyle \frac{3}{6} - \frac{1}{3} \) =
- (5) \(\displaystyle \frac{3}{7} - \frac{2}{10} \) =
- (6) \(\displaystyle 1 - \frac{1}{3} \) =
- (7) \(\displaystyle \frac{4}{6} - \frac{2}{6} \) =
- (8) \(\displaystyle \frac{3}{5} - \frac{2}{7} \) =
- (9) \(\displaystyle 1 \frac{3}{9} - \frac{6}{9} \) =
- (10) \(\displaystyle \frac{6}{9} - \frac{5}{8} \) =
【解答】【小学5年】異なる分母の分数のひき算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle 1\frac{4}{7} - 1 \) = \(\displaystyle \frac{4}{7} \)
- (2) \(\displaystyle \frac{2}{7} - \frac{1}{8} \) = \(\displaystyle \frac{9}{56} \)
- (3) \(\displaystyle \frac{2}{8} - \frac{1}{8} \) = \(\displaystyle \frac{1}{8} \)
- (4) \(\displaystyle \frac{3}{6} - \frac{1}{3} \) = \(\displaystyle \frac{1}{6} \)
- (5) \(\displaystyle \frac{3}{7} - \frac{2}{10} \) = \(\displaystyle \frac{8}{35} \)
- (6) \(\displaystyle 1 - \frac{1}{3} \) = \(\displaystyle \frac{2}{3} \)
- (7) \(\displaystyle \frac{4}{6} - \frac{2}{6} \) = \(\displaystyle \frac{1}{3} \)
- (8) \(\displaystyle \frac{3}{5} - \frac{2}{7} \) = \(\displaystyle \frac{11}{35} \)
- (9) \(\displaystyle 1\frac{3}{9} - \frac{6}{9} \) = \(\displaystyle \frac{2}{3} \)
- (10) \(\displaystyle \frac{6}{9} - \frac{5}{8} \) = \(\displaystyle \frac{1}{24} \)