【小学5年】異なる分母の分数のひき算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle \frac{2}{3} - \frac{4}{10} \) =
- (2) \(\displaystyle 1 \frac{2}{5} - \frac{2}{9} \) =
- (3) \(\displaystyle 1 \frac{2}{5} - \frac{3}{7} \) =
- (4) \(\displaystyle \frac{8}{9} - \frac{1}{3} \) =
- (5) \(\displaystyle \frac{2}{5} - \frac{1}{6} \) =
- (6) \(\displaystyle 1 \frac{1}{3} - 1 \) =
- (7) \(\displaystyle 2 \frac{1}{3} - \frac{1}{3} \) =
- (8) \(\displaystyle 1 - \frac{1}{3} \) =
- (9) \(\displaystyle 1 \frac{1}{3} - 1 \) =
- (10) \(\displaystyle \frac{2}{10} - \frac{1}{10} \) =
【解答】【小学5年】異なる分母の分数のひき算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle \frac{2}{3} - \frac{4}{10} \) = \(\displaystyle \frac{4}{15} \)
- (2) \(\displaystyle 1\frac{2}{5} - \frac{2}{9} \) = \(\displaystyle 1\frac{8}{45} \)
- (3) \(\displaystyle 1\frac{2}{5} - \frac{3}{7} \) = \(\displaystyle \frac{34}{35} \)
- (4) \(\displaystyle \frac{8}{9} - \frac{1}{3} \) = \(\displaystyle \frac{5}{9} \)
- (5) \(\displaystyle \frac{2}{5} - \frac{1}{6} \) = \(\displaystyle \frac{7}{30} \)
- (6) \(\displaystyle 1\frac{1}{3} - 1 \) = \(\displaystyle \frac{1}{3} \)
- (7) \(\displaystyle 2\frac{1}{3} - \frac{1}{3} \) = \(\displaystyle 2 \)
- (8) \(\displaystyle 1 - \frac{1}{3} \) = \(\displaystyle \frac{2}{3} \)
- (9) \(\displaystyle 1\frac{1}{3} - 1 \) = \(\displaystyle \frac{1}{3} \)
- (10) \(\displaystyle \frac{2}{10} - \frac{1}{10} \) = \(\displaystyle \frac{1}{10} \)