【小学4年】仮分数・帯分数のひき算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle \frac{6}{3} - \frac{2}{3} \) =
- (2) \(\displaystyle \frac{9}{10} - \frac{8}{10} \) =
- (3) \(\displaystyle \frac{3}{3} - \frac{2}{3} \) =
- (4) \(\displaystyle \frac{3}{3} - \frac{1}{3} \) =
- (5) \(\displaystyle \frac{9}{5} - \frac{7}{5} \) =
- (6) \(\displaystyle 1 \frac{1}{6} - \frac{3}{6} \) =
- (7) \(\displaystyle \frac{8}{9} - \frac{7}{9} \) =
- (8) \(\displaystyle 1 \frac{4}{5} - \frac{2}{5} \) =
- (9) \(\displaystyle \frac{6}{9} - \frac{2}{9} \) =
- (10) \(\displaystyle \frac{3}{7} - \frac{1}{7} \) =
【解答】【小学4年】仮分数・帯分数のひき算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle \frac{6}{3} - \frac{2}{3}\) = \(\displaystyle 1\frac{1}{3}\)
- (2) \(\displaystyle \frac{9}{10} - \frac{8}{10}\) = \(\displaystyle \frac{1}{10}\)
- (3) \(\displaystyle \frac{3}{3} - \frac{2}{3}\) = \(\displaystyle \frac{1}{3}\)
- (4) \(\displaystyle \frac{3}{3} - \frac{1}{3}\) = \(\displaystyle \frac{2}{3}\)
- (5) \(\displaystyle \frac{9}{5} - \frac{7}{5}\) = \(\displaystyle \frac{2}{5}\)
- (6) \(\displaystyle 1\frac{1}{6} - \frac{3}{6}\) = \(\displaystyle \frac{4}{6}\)
- (7) \(\displaystyle \frac{8}{9} - \frac{7}{9}\) = \(\displaystyle \frac{1}{9}\)
- (8) \(\displaystyle 1\frac{4}{5} - \frac{2}{5}\) = \(\displaystyle 1\frac{2}{5}\)
- (9) \(\displaystyle \frac{6}{9} - \frac{2}{9}\) = \(\displaystyle \frac{4}{9}\)
- (10) \(\displaystyle \frac{3}{7} - \frac{1}{7}\) = \(\displaystyle \frac{2}{7}\)