【小学4年】仮分数・帯分数のたし算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle \frac{10}{3} + \frac{10}{3} \) =
- (2) \(\displaystyle \frac{3}{6} + \frac{5}{6} \) =
- (3) \(\displaystyle \frac{5}{10} + \frac{12}{10} \) =
- (4) \(\displaystyle \frac{10}{4} + \frac{12}{4} \) =
- (5) \(\displaystyle \frac{9}{5} + \frac{6}{5} \) =
- (6) \(\displaystyle \frac{3}{6} + 2 \) =
- (7) \(\displaystyle 2 \frac{3}{4} + 1 \) =
- (8) \(\displaystyle \frac{4}{6} + 1 \frac{4}{6} \) =
- (9) \(\displaystyle 1 + 1 \frac{3}{7} \) =
- (10) \(\displaystyle \frac{3}{7} + 1 \frac{4}{7} \) =
【解答】【小学4年】仮分数・帯分数のたし算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle \frac{10}{3} + \frac{10}{3}\) = \(\displaystyle 6\frac{2}{3}\)
- (2) \(\displaystyle \frac{3}{6} + \frac{5}{6}\) = \(\displaystyle 1\frac{2}{6}\)
- (3) \(\displaystyle \frac{5}{10} + \frac{12}{10}\) = \(\displaystyle 1\frac{7}{10}\)
- (4) \(\displaystyle \frac{10}{4} + \frac{12}{4}\) = \(\displaystyle 5\frac{2}{4}\)
- (5) \(\displaystyle \frac{9}{5} + \frac{6}{5}\) = \(\displaystyle 3\)
- (6) \(\displaystyle \frac{3}{6} + 2\) = \(\displaystyle 2\frac{3}{6}\)
- (7) \(\displaystyle 2\frac{3}{4} + 1\) = \(\displaystyle 3\frac{3}{4}\)
- (8) \(\displaystyle \frac{4}{6} + 1\frac{4}{6}\) = \(\displaystyle 2\frac{2}{6}\)
- (9) \(\displaystyle 1 + 1\frac{3}{7}\) = \(\displaystyle 2\frac{3}{7}\)
- (10) \(\displaystyle \frac{3}{7} + 1\frac{4}{7}\) = \(\displaystyle 2\)