【小学4年】仮分数・帯分数のたし算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle \frac{8}{9} + \frac{3}{9} \) =
- (2) \(\displaystyle \frac{8}{3} + \frac{9}{3} \) =
- (3) \(\displaystyle \frac{3}{4} + \frac{10}{4} \) =
- (4) \(\displaystyle \frac{8}{9} + \frac{2}{9} \) =
- (5) \(\displaystyle \frac{8}{5} + \frac{7}{5} \) =
- (6) \(\displaystyle \frac{6}{10} + 1 \) =
- (7) \(\displaystyle \frac{8}{9} + \frac{1}{9} \) =
- (8) \(\displaystyle 1 + \frac{8}{10} \) =
- (9) \(\displaystyle \frac{4}{8} + \frac{2}{8} \) =
- (10) \(\displaystyle \frac{2}{10} + 1 \frac{1}{10} \) =
【解答】【小学4年】仮分数・帯分数のたし算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle \frac{8}{9} + \frac{3}{9}\) = \(\displaystyle 1\frac{2}{9}\)
- (2) \(\displaystyle \frac{8}{3} + \frac{9}{3}\) = \(\displaystyle 5\frac{2}{3}\)
- (3) \(\displaystyle \frac{3}{4} + \frac{10}{4}\) = \(\displaystyle 3\frac{1}{4}\)
- (4) \(\displaystyle \frac{8}{9} + \frac{2}{9}\) = \(\displaystyle 1\frac{1}{9}\)
- (5) \(\displaystyle \frac{8}{5} + \frac{7}{5}\) = \(\displaystyle 3\)
- (6) \(\displaystyle \frac{6}{10} + 1\) = \(\displaystyle 1\frac{6}{10}\)
- (7) \(\displaystyle \frac{8}{9} + \frac{1}{9}\) = \(\displaystyle 1\)
- (8) \(\displaystyle 1 + \frac{8}{10}\) = \(\displaystyle 1\frac{8}{10}\)
- (9) \(\displaystyle \frac{4}{8} + \frac{2}{8}\) = \(\displaystyle \frac{6}{8}\)
- (10) \(\displaystyle \frac{2}{10} + 1\frac{1}{10}\) = \(\displaystyle 1\frac{3}{10}\)