【小学5年】異なる分母の分数のたし算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle 1 \frac{2}{10} + \frac{6}{10} \) =
- (2) \(\displaystyle 1 + \frac{7}{10} \) =
- (3) \(\displaystyle \frac{4}{6} + \frac{4}{7} \) =
- (4) \(\displaystyle 2 + \frac{7}{8} \) =
- (5) \(\displaystyle \frac{3}{5} + \frac{1}{8} \) =
- (6) \(\displaystyle 2 + 1 \frac{1}{8} \) =
- (7) \(\displaystyle 1 + 1 \frac{2}{7} \) =
- (8) \(\displaystyle \frac{2}{10} + \frac{6}{9} \) =
- (9) \(\displaystyle \frac{6}{9} + 1 \frac{2}{5} \) =
- (10) \(\displaystyle 1 \frac{4}{8} + 2 \frac{1}{3} \) =
【解答】【小学5年】異なる分母の分数のたし算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle 1 \frac{2}{10} + \frac{6}{10} \) = \(\displaystyle 1 \frac{4}{5} \)
- (2) \(\displaystyle 1 + \frac{7}{10} \) = \(\displaystyle 1 \frac{7}{10} \)
- (3) \(\displaystyle \frac{4}{6} + \frac{4}{7} \) = \(\displaystyle 1 \frac{5}{21} \)
- (4) \(\displaystyle 2 + \frac{7}{8} \) = \(\displaystyle 2 \frac{7}{8} \)
- (5) \(\displaystyle \frac{3}{5} + \frac{1}{8} \) = \(\displaystyle \frac{29}{40} \)
- (6) \(\displaystyle 2 + 1 \frac{1}{8} \) = \(\displaystyle 3 \frac{1}{8} \)
- (7) \(\displaystyle 1 + 1 \frac{2}{7} \) = \(\displaystyle 2 \frac{2}{7} \)
- (8) \(\displaystyle \frac{2}{10} + \frac{6}{9} \) = \(\displaystyle \frac{13}{15} \)
- (9) \(\displaystyle \frac{6}{9} + 1 \frac{2}{5} \) = \(\displaystyle 2 \frac{1}{15} \)
- (10) \(\displaystyle 1 \frac{4}{8} + 2 \frac{1}{3} \) = \(\displaystyle 3 \frac{5}{6} \)