【小学6年】帯分数のかけ算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle 1 \frac{1}{4} × 1 \) =
- (2) \(\displaystyle \frac{1}{7} × 1 \frac{2}{5} \) =
- (3) \(\displaystyle \frac{6}{8} × \frac{1}{10} \) =
- (4) \(\displaystyle 3 × 1 \frac{3}{8} \) =
- (5) \(\displaystyle 2 \frac{1}{4} × 1 \frac{5}{7} \) =
- (6) \(\displaystyle \frac{2}{7} × 1 \frac{1}{9} \) =
- (7) \(\displaystyle \frac{3}{7} × \frac{1}{9} \) =
- (8) \(\displaystyle \frac{2}{3} × \frac{1}{6} \) =
- (9) \(\displaystyle 2 \frac{1}{4} × 2 \frac{1}{3} \) =
- (10) \(\displaystyle 2 \frac{2}{3} × 2 \frac{1}{2} \) =
【解答】【小学6年】帯分数のかけ算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle 1 \frac{1}{4} × 1 \) = \(\displaystyle 1 \frac{1}{4} \)
- (2) \(\displaystyle \frac{1}{7} × 1 \frac{2}{5} \) = \(\displaystyle \frac{1}{5} \)
- (3) \(\displaystyle \frac{6}{8} × \frac{1}{10} \) = \(\displaystyle \frac{3}{40} \)
- (4) \(\displaystyle 3 × 1 \frac{3}{8} \) = \(\displaystyle 4 \frac{1}{8} \)
- (5) \(\displaystyle 2 \frac{1}{4} × 1 \frac{5}{7} \) = \(\displaystyle 3 \frac{6}{7} \)
- (6) \(\displaystyle \frac{2}{7} × 1 \frac{1}{9} \) = \(\displaystyle \frac{20}{63} \)
- (7) \(\displaystyle \frac{3}{7} × \frac{1}{9} \) = \(\displaystyle \frac{1}{21} \)
- (8) \(\displaystyle \frac{2}{3} × \frac{1}{6} \) = \(\displaystyle \frac{1}{9} \)
- (9) \(\displaystyle 2 \frac{1}{4} × 2 \frac{1}{3} \) = \(\displaystyle 5 \frac{1}{4} \)
- (10) \(\displaystyle 2 \frac{2}{3} × 2 \frac{1}{2} \) = \(\displaystyle 6 \frac{2}{3} \)