【小学6年】帯分数のかけ算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle 1 × \frac{4}{8} \) =
- (2) \(\displaystyle \frac{3}{9} × 2 \frac{1}{2} \) =
- (3) \(\displaystyle 1 \frac{2}{10} × 1 \) =
- (4) \(\displaystyle 1 × \frac{3}{7} \) =
- (5) \(\displaystyle \frac{1}{8} × 1 \) =
- (6) \(\displaystyle 1 × 1 \frac{1}{4} \) =
- (7) \(\displaystyle \frac{1}{5} × 1 \frac{1}{4} \) =
- (8) \(\displaystyle 2 × 1 \frac{5}{6} \) =
- (9) \(\displaystyle \frac{6}{7} × 2 \) =
- (10) \(\displaystyle 1 \frac{2}{3} × 2 \) =
【解答】【小学6年】帯分数のかけ算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle 1 × \frac{4}{8} \) = \(\displaystyle \frac{1}{2} \)
- (2) \(\displaystyle \frac{3}{9} × 2 \frac{1}{2} \) = \(\displaystyle \frac{5}{6} \)
- (3) \(\displaystyle 1 \frac{2}{10} × 1 \) = \(\displaystyle 1 \frac{1}{5} \)
- (4) \(\displaystyle 1 × \frac{3}{7} \) = \(\displaystyle \frac{3}{7} \)
- (5) \(\displaystyle \frac{1}{8} × 1 \) = \(\displaystyle \frac{1}{8} \)
- (6) \(\displaystyle 1 × 1 \frac{1}{4} \) = \(\displaystyle 1 \frac{1}{4} \)
- (7) \(\displaystyle \frac{1}{5} × 1 \frac{1}{4} \) = \(\displaystyle \frac{1}{4} \)
- (8) \(\displaystyle 2 × 1 \frac{5}{6} \) = \(\displaystyle 3 \frac{2}{3} \)
- (9) \(\displaystyle \frac{6}{7} × 2 \) = \(\displaystyle 1 \frac{5}{7} \)
- (10) \(\displaystyle 1 \frac{2}{3} × 2 \) = \(\displaystyle 3 \frac{1}{3} \)