【小学6年】帯分数のかけ算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle \frac{1}{7} × 1 \frac{3}{9} \) =
- (2) \(\displaystyle 2 \frac{2}{3} × 1 \frac{2}{5} \) =
- (3) \(\displaystyle \frac{6}{10} × \frac{7}{9} \) =
- (4) \(\displaystyle 4 × \frac{3}{8} \) =
- (5) \(\displaystyle 2 \frac{2}{4} × 1 \frac{3}{7} \) =
- (6) \(\displaystyle 1 \frac{2}{9} × \frac{1}{5} \) =
- (7) \(\displaystyle 1 × 4 \) =
- (8) \(\displaystyle 1 \frac{3}{4} × 1 \frac{3}{6} \) =
- (9) \(\displaystyle \frac{2}{3} × 2 \frac{1}{2} \) =
- (10) \(\displaystyle \frac{4}{7} × 2 \) =
【解答】【小学6年】帯分数のかけ算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle \frac{1}{7} × 1 \frac{3}{9} \) = \(\displaystyle \frac{4}{21} \)
- (2) \(\displaystyle 2 \frac{2}{3} × 1 \frac{2}{5} \) = \(\displaystyle 3 \frac{11}{15} \)
- (3) \(\displaystyle \frac{6}{10} × \frac{7}{9} \) = \(\displaystyle \frac{7}{15} \)
- (4) \(\displaystyle 4 × \frac{3}{8} \) = \(\displaystyle 1 \frac{1}{2} \)
- (5) \(\displaystyle 2 \frac{2}{4} × 1 \frac{3}{7} \) = \(\displaystyle 3 \frac{4}{7} \)
- (6) \(\displaystyle 1 \frac{2}{9} × \frac{1}{5} \) = \(\displaystyle \frac{11}{45} \)
- (7) \(\displaystyle 1 × 4 \) = \(\displaystyle 4 \)
- (8) \(\displaystyle 1 \frac{3}{4} × 1 \frac{3}{6} \) = \(\displaystyle 2 \frac{5}{8} \)
- (9) \(\displaystyle \frac{2}{3} × 2 \frac{1}{2} \) = \(\displaystyle 1 \frac{2}{3} \)
- (10) \(\displaystyle \frac{4}{7} × 2 \) = \(\displaystyle 1 \frac{1}{7} \)