【小学6年】帯分数のかけ算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle 1 × \frac{9}{10} \) =
- (2) \(\displaystyle 5 × \frac{2}{9} \) =
- (3) \(\displaystyle 1 \frac{5}{6} × 1 \frac{1}{6} \) =
- (4) \(\displaystyle 1 \frac{4}{7} × \frac{1}{3} \) =
- (5) \(\displaystyle 6 × \frac{4}{9} \) =
- (6) \(\displaystyle \frac{2}{4} × 3 \frac{1}{2} \) =
- (7) \(\displaystyle 3 \frac{1}{2} × \frac{1}{9} \) =
- (8) \(\displaystyle \frac{6}{8} × 1 \frac{3}{7} \) =
- (9) \(\displaystyle 1 \frac{1}{10} × \frac{5}{8} \) =
- (10) \(\displaystyle \frac{6}{9} × 1 \frac{4}{6} \) =
【解答】【小学6年】帯分数のかけ算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle 1 × \frac{9}{10} \) = \(\displaystyle \frac{9}{10} \)
- (2) \(\displaystyle 5 × \frac{2}{9} \) = \(\displaystyle 1 \frac{1}{9} \)
- (3) \(\displaystyle 1 \frac{5}{6} × 1 \frac{1}{6} \) = \(\displaystyle 2 \frac{5}{36} \)
- (4) \(\displaystyle 1 \frac{4}{7} × \frac{1}{3} \) = \(\displaystyle \frac{11}{21} \)
- (5) \(\displaystyle 6 × \frac{4}{9} \) = \(\displaystyle 2 \frac{2}{3} \)
- (6) \(\displaystyle \frac{2}{4} × 3 \frac{1}{2} \) = \(\displaystyle 1 \frac{3}{4} \)
- (7) \(\displaystyle 3 \frac{1}{2} × \frac{1}{9} \) = \(\displaystyle \frac{7}{18} \)
- (8) \(\displaystyle \frac{6}{8} × 1 \frac{3}{7} \) = \(\displaystyle 1 \frac{1}{14} \)
- (9) \(\displaystyle 1 \frac{1}{10} × \frac{5}{8} \) = \(\displaystyle \frac{11}{16} \)
- (10) \(\displaystyle \frac{6}{9} × 1 \frac{4}{6} \) = \(\displaystyle 1 \frac{1}{9} \)