【小学6年】帯分数のわり算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle 3 \frac{1}{2} ÷ \frac{6}{9} \) =
- (2) \(\displaystyle \frac{4}{10} ÷ 1 \frac{3}{6} \) =
- (3) \(\displaystyle 1 \frac{2}{10} ÷ 2 \frac{2}{3} \) =
- (4) \(\displaystyle 3 ÷ \frac{2}{7} \) =
- (5) \(\displaystyle 1 \frac{2}{3} ÷ \frac{1}{7} \) =
- (6) \(\displaystyle 1 \frac{1}{4} ÷ \frac{2}{10} \) =
- (7) \(\displaystyle \frac{3}{4} ÷ \frac{7}{9} \) =
- (8) \(\displaystyle 2 ÷ 1 \frac{1}{8} \) =
- (9) \(\displaystyle \frac{4}{6} ÷ 1 \frac{4}{8} \) =
- (10) \(\displaystyle 2 \frac{2}{3} ÷ 2 \) =
【解答】【小学6年】帯分数のわり算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle 3 \frac{1}{2} ÷ \frac{6}{9} \) = \(\displaystyle 5 \frac{1}{4} \)
- (2) \(\displaystyle \frac{4}{10} ÷ 1 \frac{3}{6} \) = \(\displaystyle \frac{4}{15} \)
- (3) \(\displaystyle 1 \frac{2}{10} ÷ 2 \frac{2}{3} \) = \(\displaystyle \frac{9}{20} \)
- (4) \(\displaystyle 3 ÷ \frac{2}{7} \) = \(\displaystyle 10 \frac{1}{2} \)
- (5) \(\displaystyle 1 \frac{2}{3} ÷ \frac{1}{7} \) = \(\displaystyle 11 \frac{2}{3} \)
- (6) \(\displaystyle 1 \frac{1}{4} ÷ \frac{2}{10} \) = \(\displaystyle 6 \frac{1}{4} \)
- (7) \(\displaystyle \frac{3}{4} ÷ \frac{7}{9} \) = \(\displaystyle \frac{27}{28} \)
- (8) \(\displaystyle 2 ÷ 1 \frac{1}{8} \) = \(\displaystyle 1 \frac{7}{9} \)
- (9) \(\displaystyle \frac{4}{6} ÷ 1 \frac{4}{8} \) = \(\displaystyle \frac{4}{9} \)
- (10) \(\displaystyle 2 \frac{2}{3} ÷ 2 \) = \(\displaystyle 1 \frac{1}{3} \)