【小学6年】帯分数のわり算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle \frac{2}{4} ÷ \frac{5}{7} \) =
- (2) \(\displaystyle \frac{5}{7} ÷ \frac{2}{3} \) =
- (3) \(\displaystyle \frac{9}{10} ÷ \frac{2}{9} \) =
- (4) \(\displaystyle \frac{9}{10} ÷ 1 \frac{1}{5} \) =
- (5) \(\displaystyle \frac{1}{2} ÷ \frac{6}{10} \) =
- (6) \(\displaystyle 1 \frac{2}{6} ÷ 1 \) =
- (7) \(\displaystyle 1 \frac{5}{6} ÷ 1 \frac{2}{4} \) =
- (8) \(\displaystyle 1 \frac{4}{8} ÷ 1 \frac{3}{8} \) =
- (9) \(\displaystyle 2 \frac{1}{5} ÷ 1 \frac{1}{5} \) =
- (10) \(\displaystyle \frac{1}{9} ÷ 2 \) =
【解答】【小学6年】帯分数のわり算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle \frac{2}{4} ÷ \frac{5}{7} \) = \(\displaystyle \frac{7}{10} \)
- (2) \(\displaystyle \frac{5}{7} ÷ \frac{2}{3} \) = \(\displaystyle 1 \frac{1}{14} \)
- (3) \(\displaystyle \frac{9}{10} ÷ \frac{2}{9} \) = \(\displaystyle 4 \frac{1}{20} \)
- (4) \(\displaystyle \frac{9}{10} ÷ 1 \frac{1}{5} \) = \(\displaystyle \frac{3}{4} \)
- (5) \(\displaystyle \frac{1}{2} ÷ \frac{6}{10} \) = \(\displaystyle \frac{5}{6} \)
- (6) \(\displaystyle 1 \frac{2}{6} ÷ 1 \) = \(\displaystyle 1 \frac{1}{3} \)
- (7) \(\displaystyle 1 \frac{5}{6} ÷ 1 \frac{2}{4} \) = \(\displaystyle 1 \frac{2}{9} \)
- (8) \(\displaystyle 1 \frac{4}{8} ÷ 1 \frac{3}{8} \) = \(\displaystyle 1 \frac{1}{11} \)
- (9) \(\displaystyle 2 \frac{1}{5} ÷ 1 \frac{1}{5} \) = \(\displaystyle 1 \frac{5}{6} \)
- (10) \(\displaystyle \frac{1}{9} ÷ 2 \) = \(\displaystyle \frac{1}{18} \)