【小学6年】帯分数のわり算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle 1 ÷ 1 \frac{3}{6} \) =
- (2) \(\displaystyle \frac{4}{9} ÷ 1 \frac{4}{5} \) =
- (3) \(\displaystyle 2 ÷ 2 \) =
- (4) \(\displaystyle \frac{5}{9} ÷ 1 \) =
- (5) \(\displaystyle 1 \frac{2}{4} ÷ 1 \frac{2}{9} \) =
- (6) \(\displaystyle 2 ÷ 1 \frac{1}{5} \) =
- (7) \(\displaystyle \frac{4}{5} ÷ \frac{3}{4} \) =
- (8) \(\displaystyle \frac{3}{7} ÷ \frac{6}{9} \) =
- (9) \(\displaystyle 1 \frac{3}{9} ÷ 2 \) =
- (10) \(\displaystyle 3 ÷ \frac{1}{10} \) =
【解答】【小学6年】帯分数のわり算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle 1 ÷ 1 \frac{3}{6} \) = \(\displaystyle \frac{2}{3} \)
- (2) \(\displaystyle \frac{4}{9} ÷ 1 \frac{4}{5} \) = \(\displaystyle \frac{20}{81} \)
- (3) \(\displaystyle 2 ÷ 2 \) = \(\displaystyle 1 \)
- (4) \(\displaystyle \frac{5}{9} ÷ 1 \) = \(\displaystyle \frac{5}{9} \)
- (5) \(\displaystyle 1 \frac{2}{4} ÷ 1 \frac{2}{9} \) = \(\displaystyle 1 \frac{5}{22} \)
- (6) \(\displaystyle 2 ÷ 1 \frac{1}{5} \) = \(\displaystyle 1 \frac{2}{3} \)
- (7) \(\displaystyle \frac{4}{5} ÷ \frac{3}{4} \) = \(\displaystyle 1 \frac{1}{15} \)
- (8) \(\displaystyle \frac{3}{7} ÷ \frac{6}{9} \) = \(\displaystyle \frac{9}{14} \)
- (9) \(\displaystyle 1 \frac{3}{9} ÷ 2 \) = \(\displaystyle \frac{2}{3} \)
- (10) \(\displaystyle 3 ÷ \frac{1}{10} \) = \(\displaystyle 30 \)