【小学6年】帯分数のわり算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle 1 \frac{3}{6} ÷ \frac{7}{9} \) =
- (2) \(\displaystyle 1 \frac{2}{7} ÷ \frac{1}{9} \) =
- (3) \(\displaystyle 1 \frac{2}{10} ÷ 4 \) =
- (4) \(\displaystyle 1 ÷ 2 \frac{2}{3} \) =
- (5) \(\displaystyle 1 ÷ \frac{1}{3} \) =
- (6) \(\displaystyle 1 \frac{3}{9} ÷ \frac{2}{8} \) =
- (7) \(\displaystyle \frac{3}{5} ÷ 2 \frac{2}{5} \) =
- (8) \(\displaystyle 3 ÷ 3 \) =
- (9) \(\displaystyle 1 \frac{4}{5} ÷ 3 \) =
- (10) \(\displaystyle \frac{2}{5} ÷ \frac{4}{9} \) =
【解答】【小学6年】帯分数のわり算プリント
日付:
次の計算をしなさい。
- (1) \(\displaystyle 1 \frac{3}{6} ÷ \frac{7}{9} \) = \(\displaystyle 1 \frac{13}{14} \)
- (2) \(\displaystyle 1 \frac{2}{7} ÷ \frac{1}{9} \) = \(\displaystyle 11 \frac{4}{7} \)
- (3) \(\displaystyle 1 \frac{2}{10} ÷ 4 \) = \(\displaystyle \frac{3}{10} \)
- (4) \(\displaystyle 1 ÷ 2 \frac{2}{3} \) = \(\displaystyle \frac{3}{8} \)
- (5) \(\displaystyle 1 ÷ \frac{1}{3} \) = \(\displaystyle 3 \)
- (6) \(\displaystyle 1 \frac{3}{9} ÷ \frac{2}{8} \) = \(\displaystyle 5 \frac{1}{3} \)
- (7) \(\displaystyle \frac{3}{5} ÷ 2 \frac{2}{5} \) = \(\displaystyle \frac{1}{4} \)
- (8) \(\displaystyle 3 ÷ 3 \) = \(\displaystyle 1 \)
- (9) \(\displaystyle 1 \frac{4}{5} ÷ 3 \) = \(\displaystyle \frac{3}{5} \)
- (10) \(\displaystyle \frac{2}{5} ÷ \frac{4}{9} \) = \(\displaystyle \frac{9}{10} \)