- 1-1 式の計算
- 1-2 式の利用
- 2-1 連立方程式の解き方
- 2-2 連立方程式の利用
- 3-1 1次関数
- 3-2 1次関数と方程式
- 4-1 平行線と角
- 4-2 合同と証明
- 5-1 三角形
- 5-2 四角形
- 6-1 確率
- 7-1 データの活用
【中学2年数学】1-1 式の計算｜問題集
1.次の多項式の項と次数を答えなさい。
(1)\(x+3y\)
(2)\(2x+xy\)
(3)\(2a-5b+1\)
(4)\(a^2-4ab+4b^2\)
(5)\(2x+7y\)
(6)\(3xy-x+1\)
(7)\(2a^2+3ab+2b-5\)
(8)\(x^2-6x^2y+3y\)
2.次の式を計算しなさい。
(1)\(x^2+6x+2x^2-3x\)
(2)\(2x+4xy-7x-2xy\)
(3)\(-2x+5y+8x-3y\)
(4)\(9x^2+3xy-2x^2-7xy\)
(5)\(4x+3y-x\)
(6)\(5a-2b+2a-4b+7\)
(7)\(a^2-0.4a+2a^2+0.5a\)
(8)\(\displaystyle \frac{2}{3}x-y-\frac{1}{6}x+3y\)
(9)\(3x-2y-x\)
(10)\(-4a+2b+3a-b\)
(11)\(9x^2-2xy+5x^2+3xy\)
(12)\(\displaystyle a^2+\frac{ab}{4}-3a^2+\frac{ab}{3}\)
(13)\(x+3y-y\)
(14)\(3a-4b-2a+b\)
(15)\(-7x+2y+6x-2y\)
(16)\(6a^2+a-7a^2-2a\)
(17)\((2x+y)+(5x+6y)\)
(18)\((3a-4b)+(-2a+7b)\)
(19)\((-2x+4y)+(10x-6y)\)
(20)\((5x^2+4x-2)+(x^2-3x+1)\)
(21)\((4x+7y)-(3x+y)\)
(22)\((2x+5y)-(4x-3y)\)
(23)\((6a-2b)-(-3a+4b)\)
(24)\((x^2-2x-3)-(6x^2-4x+1)\)
(25)\((x+5y)+(2x-7y)\)
(26)\((2a-b)-(6a-5b)\)
(27)\((2a-b)+(a+5b)\)
(28)\((x-y)-(-7x+2y)\)
(29)\((6x-3y)+(2x+5y)\)
(30)\((2a-b)+(-3a+2b)\)
(31)\((2x^2+xy-y^2)+(-3x^2-2xy+3y^2)\)
(32)\((3x-4y)-(-2x+y)\)
(33)\((a+2b)-(3a-4b)\)
(34)\((x^2-2xy+y^2)-(-x^2+xy-4y^2)\)
(35)\((7x-5y)+(-5x+7y)\)
(36)\((3a-b)-(-2a+5b)\)
(37)\(\displaystyle \left(\frac{x}{3}+\frac{y}{2}\right)+\left(\frac{x}{2}-\frac{5}{2}y\right)\)
(38)\(\displaystyle \left(\frac{x}{2}-y\right)-\left(\frac{2}{3}x-\frac{y}{3}\right)\)
(39)\((3x-y)+(2x+5y)\)
(40)\((a^2+2ab-b^2)+(a^2-ab+b^2)\)
(41)\((8x-5y)-(4x-6y)\)
(42)\((2x^2+2x-4)-(x^2+3x-5)\)
(43)\((3x-5y)+(2x+3y)\)
(44)\((9a-10b)-(6a-7b)\)
(45)\(3x×2y\)
(46)\(4a×(-3b)\)
(47)\((-x)×(-5y)\)
(48)\((-7a)×2a\)
(49)\(\displaystyle \frac{1}{3}x×(-6y)\)
(50)\(\displaystyle (-4ab)×\left(-\frac{1}{8}c\right)\)
(51)\(12xy÷2y\)
(52)\(8x^2÷4x\)
(53)\(\displaystyle 2ab÷\frac{1}{2}b\)
(54)\(\displaystyle 4xy÷\frac{8}{5}x\)
(55)\(3x×2xy÷6y\)
(56)\(20a^2b^2÷(-5b)÷2ab\)
(57)\(16x^2y÷8y\)
(58)\((-21a^2b^2)÷(-6ab)\)
(59)\(\displaystyle 9x^2y÷(-\frac{3}{4}x)\)
(60)\(\displaystyle \left(-\frac{4}{3}a^2b\right)÷\frac{7}{6}ab\)
(61)\(3(a+2b)\)
(62)\(-2(5x+2y)\)
(63)\(\displaystyle (a-5b)×\frac{1}{5}\)
(64)\(\displaystyle 6\left(\frac{x}{2}-\frac{y}{3}\right)\)
(65)\((8a+4b)÷2\)
(66)\((3x-12y)÷(-3)\)
(67)\((-7a-21b)÷(-7)\)
(68)\(\displaystyle (3x-6y)÷\frac{3}{2}\)
(69)\(2(2x-y)+3(x+4y)\)
(70)\(5(3x+2y)-2(5x+4y)\)
(71)\(2(2a+3b)+3(a-4b)\)
(72)\(4(3x-2y)-7(2x-y)\)
(73)\(6(x^2-x+2)+3(x^2+2x-2)\)
(74)\(2(2x^2+3x-5)-3(x^2+3x-2)\)
(75)\((6x-2y)-(x-7y)\)
(76)\(2(3x-y)+4(-x+2y)\)
(77)\(2(x+5y)+3(x-3y)\)
(78)\(6(x-2y)-4(x-3y)\)
(79)\(7(-2x+y)+4(3x-4y)\)
(80)\(3(2a-3b)-5(a-2b)\)
(81)\(2(3a+2b)+4(a-3b)\)
(82)\(6(x-2y)-5(-2x+y)\)
(83)\(-3(2a+3b)-(7a-4b)\)
(84)\(-2(3x-2y)+3(-x+2y)\)
(85)\(5(4x+2y)-2(-5x-4y)\)
(86)\(3(-2a+5b)+4(a+6b)\)
(87)\(\displaystyle \frac{x+2y}{3}+\frac{2x-y}{2}\)
(88)\(\displaystyle \frac{3a-2b}{4}-\frac{a-2b}{2}\)
(89)\(\displaystyle 3x-y+\frac{x+4y}{3}\)
(90)\(\displaystyle \frac{2a+b}{2}-\frac{3a-b}{5}\)
(91)\(\displaystyle \frac{2a+3b}{7}+a-2b\)
(92)\(\displaystyle \frac{5x-7y}{8}-\frac{2x-3y}{2}\)
3.\(x=-2,y=4\)のとき、次の式の値を求めなさい。
(1)\(2(3x+y)-3(2x+4y)\)
(2)\(28x^2y^2÷(-2y)÷7x\)
4.\(x=4,y=-6\)のとき、次の式の値を求めなさい。
(1)\(5(2x-3y)-7(x-2y)\)
(2)\(3x^3y×(-8y)÷(-6x^2y)\)
次の学習に進もう！