【中学1年数学】3-1 方程式の解き方|問題集

1.次の方程式を解きなさい。

(1)\(x+5=8\)
(2)\(x-3=-1\)
(3)\(4+x=2\)
(4)\(5x=15\)
(5)\(-3x=6\)
(6)\(\displaystyle \frac{x}{2}=-5\)
(7)\(2x-3=-11\)
(8)\(6x+5=29\)
(9)\(7x-4=1\)
(10)\(-3x+5=17\)
(11)\(5x=11x+6\)
(12)\(x=4-3x\)
(13)\(9x=10x-8\)
(14)\(-4y=-7y+2\)
(15)\(3x-4=2+x\)
(16)\(y-6=6+5y\)
(17)\(5x-8=2x-20\)
(18)\(3-2x=4x+9\)
(19)\(-x+4=3x-5\)
(20)\(2y-7=-3y+8\)
(21)\(4x-2=10\)
(22)\(9=7-2x\)
(23)\(5x-2=3x+8\)
(24)\(2x-12=6x-9\)
(25)\(x+6=-9\)
(26)\(6x=-18\)
(27)\(9x-7=11\)
(28)\(-3x-8=7\)
(29)\(6x-8=2x\)
(30)\(5x-2=3x+8\)
(31)\(7-9x=x-13\)
(32)\(4x+9=12+5x\)
(33)\(x+5=3\)
(34)\(-3x=2\)
(35)\(6-9x=-3\)
(36)\(2x+4=10\)
(37)\(-3y=-5y+8\)
(38)\(5y=6y-3\)
(39)\(5x-7=2x-21\)
(40)\(2-4x=-x+7\)
(41)\(2x-3(x+1)=4\)
(42)\(6-2(9-x)=4x\)
(43)\(2=6-(5-3x)\)
(44)\(4-3(y-1)=7y-3\)
(45)\(12-3(x-4)=0\)
(46)\(2(x-2)+1=x+8\)
(47)\(-1-2(5-x)=0\)
(48)\(-4(1-x)=8-(3x-2)\)
(49)\(2(x-5)=-6(x+2)\)
(50)\(4(x+2)-3=7\)
(51)\(2-3(x-3)=5\)
(52)\(0.5x+1.2=0.7\)
(53)\(3.4x-0.9=0.7x\)
(54)\(0.8x+0.72=0.12x\)
(55)\(0.2(x-4)=1.3\)
(56)\(0.8x-13=1.8x+0.4\)
(57)\(15-0.3x=6+0.2x\)
(58)\(0.5x-13=2.7x+0.2\)
(59)\(0.3(y-4)-2=0.4y\)
(60)\(1.3x-0.6=3.3\)
(61)\(2.4=0.36(x+7)\)
(62)\(2.4(x-2)=0.6x+2.4\)
(63)\(1.5x=2.3(3-2x)-0.8\)
(64)\(\displaystyle \frac{1}{3}x-\frac{1}{2}=\frac{3}{4}x-\frac{2}{3}\)
(65)\(\displaystyle \frac{x}{4}=2+\frac{x}{10}\)
(66)\(\displaystyle \frac{x-1}{3}-\frac{x}{5}=1\)
(67)\(\displaystyle \frac{2x+1}{8}-\frac{2x-5}{6}=2\)
(68)\(\displaystyle \frac{x}{2}-3=\frac{3}{4}-x\)
(69)\(x-\frac{x-1}{2}=2\)
(70)\(\displaystyle \frac{2}{3}x+1=\frac{x}{2}-5\)
(71)\(\displaystyle \frac{3x-10}{4}=\frac{5x-4}{2}\)
(72)\(\displaystyle \frac{x-8}{4}+2=\frac{2}{3}x\)
(73)\(\displaystyle \frac{x}{7}-2=\frac{x}{2}+3\)
(74)\(\displaystyle \frac{2x-1}{3}=\frac{x-1}{2}\)
(75)\(\displaystyle \frac{2x+3}{4}-\frac{4x-3}{6}=1\)
次の学習に進もう!