【微分積分】4-3-2 区分求積法|問題集
1.次の極限値を求めなさい。
(1)\(\displaystyle \lim_{n\to\infty}\frac{1}{n}\left(\frac{1}{n}+\frac{2}{n}+\cdots+\frac{n}{n}\right)\)
\(\displaystyle =\lim_{n\to\infty}\frac{1}{n}\sum_{k=1}^{n}\frac{k}{n}\)
\(\displaystyle =\int_0^1xdx\)
\(\displaystyle =\left[\frac{x^2}{2}\right]_0^1\)
\(\displaystyle =\frac{1}{2}\)
\(\displaystyle =\int_0^1xdx\)
\(\displaystyle =\left[\frac{x^2}{2}\right]_0^1\)
\(\displaystyle =\frac{1}{2}\)
(2)\(\displaystyle \lim_{n\to\infty}\frac{1}{n}\left(\frac{1}{2+\frac{1}{n}}+\frac{1}{2+\frac{2}{n}}+\cdots+\frac{1}{3}\right)\)
\(\displaystyle =\lim_{n\to\infty}\frac{1}{n}\sum_{k=1}^{n}\frac{1}{2+\frac{k}{n}}\)
\(\displaystyle =\int_0^1\frac{1}{2+x}dx\)
\(\displaystyle =[\log|2+x|]_0^1\)
\(\displaystyle =\log3-\log2\)
\(\displaystyle =\log\frac{3}{2}\)
\(\displaystyle =\int_0^1\frac{1}{2+x}dx\)
\(\displaystyle =[\log|2+x|]_0^1\)
\(\displaystyle =\log3-\log2\)
\(\displaystyle =\log\frac{3}{2}\)
(3)\(\displaystyle \lim_{n\to\infty}\frac{1}{n}\sum_{k=1}^{n}\sqrt{\frac{k}{n}}\)
\(\displaystyle =\int_0^1\sqrt{x}dx\)
\(\displaystyle =\left[\frac{2}{3}x^{\frac{3}{2}}\right]_0^1\)
\(\displaystyle =\frac{2}{3}\)
\(\displaystyle =\left[\frac{2}{3}x^{\frac{3}{2}}\right]_0^1\)
\(\displaystyle =\frac{2}{3}\)
(4)\(\displaystyle \lim_{n\to\infty}\left(\frac{1}{n+1}+\frac{1}{n+2}+\cdots+\frac{1}{2n}\right)\)
\(\displaystyle =\lim_{n\to\infty}\frac{1}{n}\sum_{k=1}^{n}\frac{1}{1+\frac{k}{n}}\)
\(\displaystyle =\int_1^2\frac{1}{x}dx\)
\(\displaystyle =[\log|x|]_1^2\)
\(\displaystyle =\log2-\log1\)
\(\displaystyle =\log2\)
\(\displaystyle =\int_1^2\frac{1}{x}dx\)
\(\displaystyle =[\log|x|]_1^2\)
\(\displaystyle =\log2-\log1\)
\(\displaystyle =\log2\)
(5)\(\displaystyle \lim_{n\to\infty}\sum_{k=1}^{n}\sqrt{\frac{1}{n^2+k^2}}\)
\(\displaystyle =\lim_{n\to\infty}\frac{1}{n}\sum_{k=1}^{n}\sqrt{\frac{1}{1+(\frac{k}{n})^2}}\)
\(\displaystyle =\int_0^1\sqrt{\frac{1}{1+x^2}}dx\)
\(\displaystyle =[\log|x+\sqrt{1+x^2}|]_0^1\)
\(\displaystyle =\log(1+\sqrt{2})\)
\(\displaystyle =\int_0^1\sqrt{\frac{1}{1+x^2}}dx\)
\(\displaystyle =[\log|x+\sqrt{1+x^2}|]_0^1\)
\(\displaystyle =\log(1+\sqrt{2})\)
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